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Samer Adeeb
Добавлен 25 янв 2012
Tensile Strain Capacity of Pressurized Pipeline
Tensile Strain Capacity of Pressurized Pipeline
Просмотров: 3
Видео
L Shape fixed free Pressure at the junction
Просмотров 689 месяцев назад
In this demonstration, a 90 degree elbow with a non-smooth transition in direction is modelled. Pressure is applied on the inner walls of the shell elements. Due to the change in direction, the pressure causes the elbow to open (Bourdon effect). The boundary conditions are fixed base and free upper end.
L Shape fixed free No Pressure at the junction
Просмотров 279 месяцев назад
In this demonstration, pressure is only applied on the inner walls of the straight portions. In this case, the elbow does not exhibit the Bourdon effect. The boundary conditions are: Fixed base with a free end.
Subsize Compact Tension Test with DIC
Просмотров 290Год назад
Small scale compact tension test of pipeline steel with displacement acquired using digital image correlation. Tests performed by Youssefl El-Naggar
Small scale fracture test specimens
Просмотров 1012 года назад
Prepared by Mr. Amr Mohamadien. Manufactured by: Rejent Tool and Manufacturing in Edmonton
XFEM Model SMises
Просмотров 2023 года назад
XFEM model of a pressurized pipe under bending by Meng Lin
XFEM Crack Propagation STATUSXFEM
Просмотров 1653 года назад
XFEM model of a pressurized pipe under bending by Meng Lin
XFEM Crack Propagation SMises
Просмотров 2873 года назад
XFEM model of a pressurized pipe under bending by Meng Lin
XFEM Crack Propagation PEEQ
Просмотров 1473 года назад
XFEM model of a pressurized pipe under bending by Meng Lin
Reductions due to energy considerations example
Просмотров 5184 года назад
sameradeeb-new.srv.ualberta.ca/constitutive-laws/linear-elastic-materials/#reductions-due-to-preservation-of-energy-8
7.4.3.1 Isotropic Hardening Example
Просмотров 3,4 тыс.4 года назад
sameradeeb-new.srv.ualberta.ca/constitutive-laws/plasticity/examples-and-exercises/#example-1 isotropic-hardening-2
7.4.3.2 Combined hardening example
Просмотров 2,2 тыс.4 года назад
sameradeeb-new.srv.ualberta.ca/constitutive-laws/plasticity/examples-and-exercises/#example-2 nonlinear-kinematic-hardening-7
7.4.2.4 Multi-axial von Mises Plasticity
Просмотров 9934 года назад
7.4.2.4 Multi-axial von Mises Plasticity
7.4.2.4 Associated flow rule and normality rule
Просмотров 2,5 тыс.4 года назад
7.4.2.4 Associated flow rule and normality rule
7.4.2 Mathematical Modelling of Plasticity
Просмотров 2,8 тыс.4 года назад
7.4.2 Mathematical Modelling of Plasticity
9.2 Deformation (Strain) Energy in a Continuum
Просмотров 5144 года назад
9.2 Deformation (Strain) Energy in a Continuum
6.1 Eulerian Lagrangian and 6.2 Mass Balance
Просмотров 7164 года назад
6.1 Eulerian Lagrangian and 6.2 Mass Balance
2.2.5 Einstein Summation Convention
Просмотров 2,6 тыс.4 года назад
2.2.5 Einstein Summation Convention
Not tensile testing, sorry
Hi sir! Can the Arc Length method able to solve non linear set of equation for a normal linear geometry problem
What's the solution by a fixed beam with axial uniform load
You can decouple the axial load from bending for small deformations. I.e., solve each differential equation separately and add the stresses.
Can you zoom in
Shouldn't the third component of uv cross-product be u1v2 - u2v1 instead of u1v3 - u3v1?
yeah i think so too
Geometric interpret is awesome
Hello, could you kindly point to orthographic shell example of a CLT two way Slab
Hello sir, I have a question on example 1, condition 2. Does the variable sigma_VM change at every increment or does it stay constant in the equations?
It changes. sigma_VM is function of sigma_11 and sigma_22 which are both increasing after initial yield.
@@CivE_UoA thanks so much! I have another question on example 1, condition 3 (plane strain). In plane strain, can we apply Levy-Mises equation and use sigma_33 = 0.5*sigma_11 for the plastic regime equations in 21:50?
Had a clear understanding, thank you
Around 2:18 if you were to add also isotropic hardening, how would it look?
For isotropic hardening, alpha-bar equal zero
@@Samer_Adeeb so that's perfect plastic if \sigma_y is a constant and bilinear if linear hardening using iso. Nice
@@surendrangithub7973 Exactly!
Why the value of of the Lambda^2 max = 1 is not fixed in the formula since it can not be larger than 1?
Great job explaining the Normality rule! Do you have a video about non-associated plasticity?
Sir please let us know relevant text books
Sir can you suggest any relevant book on this concept?
Why use a p when you're talking about a force F? By the way, the symbols are too small. Use your screen, mate!
There is something confusing me. The second degree equation has two solutions. How do you choose which is the right solution to use in your method? I mean, in Example 4.
So helpful, thank you!
@Samer Adeeb For Riks method can you applied displacement load. For example when you are showing the pipe under bending can we use applied rotations instead of moment along with RIKS method? Is there any difference if displacements and not forces are used?
You don't need to use the RIKS method in a displacement control simulation. The example shown here is just for demonstration, but the proper way to simulate it would be using "static general" under displacement control.
@@Samer_Adeeb I understood that, but if I decide to use a displacement load with Riks method, does it make any difference?
@@spyrosarvanitis5180 I wouldn't expect it to make a difference. It would probably converge faster.
@@Samer_Adeeb Thank you!
Can you please explain why in the first example for higher values if k implicit Euler solution was overpredicting?
Thank you,explanation is very good, but the book link is not working
But why the fN2 is equal to fN1?
@@Samer_Adeeb Does that mean that we assumed a fN2 which is equal to fn2 so that we can study the stress (like PK1) in the reference configuration instead of the current one?
@@Samer_Adeeb Thanks a lot!
the flow at 3:26...
What about tools "Fill holes" and "Keep largest"?
Thank you my man! Keep 'em videos going..
Is Euler Bernouli Beam Theory Obey Hookes Law
W O W I understood it thank you
The lack of consistency in symbols makes it difficult to understand
How to get load (eigenvalue) in load Vs displacement curve.
Hii.. I have some doubts in Abaqus. It's related to riks method. I did linear buckling analysis and I got eigenvalue.. I gave this eigenvalue as load in riks analysis... I got load Vs displacement curve but in that curve I couldn't get eigenvalue.. I got load less than that eigenvalue value..
You cannot obtain the eigenvalue from the load displacement curve.
I was in search of such a valuable vidio for many days.
Can you provide us the link of the website which calculates the stress tensor in 3D? please
The original is posted here:sameradeeb-new.srv.ualberta.ca/stress/cauchy-stress-as-a-linear-map/ We are switching to a new website and the tool will be available soon here: engcourses-uofa.ca/books/introduction-to-solid-mechanics/stress/cauchy-sensor-tensor/
holy thank you, searched for so long to find a good video like this
Thank you for the great explanation. However I would like to ask you where we can use the plastic modulus "h" in terms of " E " and "E(tan)" as given by the expression, h= (E*E(tan)/(E-E(tan)) ? In your example your determined it directly as the slope of the straight line? Thank you
Sorry, I don't understand your question.
Sorry Dr@@Samer_Adeeb , iam new to plasticity of steel so that i might not set the question correctly . The plasticity modulus was determind here with value of 606.678 MPa as ratio of yeild stress to plastic strain. But i found in some books that the plastic modulus h =(Young Modulus*Tangential Modulus)/( Young Modulus-Tangential Modulus). My qustion is, can we use this expression of h given above interm of E and E_tangential in the determination of plastic modulus of istropic linear hardening . I hope you get what i mean by this question
@@magedqasem7403 Yes, absolutely. Just be careful that the equation you listed is only applicable for a bilinear stress-strain curve.
Thank you Dr@@Samer_Adeeb
Very clear explanation. Thanks a lot
Sir, can u make a course to show how u establish the model and how to meshing?
go ahead bro
Hi, professor Do you have a playlist of solid mechanics? your videos are excellent
great video
F = Table[Subscript[Ff, i, j], {i, 1, 2}, {j, 1, 2}] F // MatrixForm dX = { }; dY = {}; dx = { }; dy={}; Listofvariables = Flatten[F] a = Solve[{dx == F.dX, dy == F.dY}, Listofvariables] F = F /. a[[1]] The text for the first problem, in case of any needs.
Thanks excellent
your channel is amazing. Thanks for everything. Please may you make video how to provide support conditions (pin-roller,fixed-fixed, etc) and loading conditions (distributed,, point load, etc) in 3D shell element using ABAQUS
What is it doing
the U of A is blessed to have him. Truly, the greatest.
I was going through a lot of books and articles to understand the implicit Euler method. it is very clear to me know. Thank you so much.
Thank you for your nice words
very nice lecture, one small note, this video is not included in the course's playlist , it can cause confusions for some viewers
Thank you for your nice words. It is included in the graduate course playlist: ruclips.net/p/PLWlJvChadvVwrkILYYvdN5si0q1CePQGL
Best Prof no competition, GOAT
E*I*y''''[x] + ro*A*y''[t]=0 isnt this the beam equation? And not E*I*y''''[x]=0?
Thank you kind sir <3